__Pythagorean Theorem__

__Right Triangle:__ 3-sided polygon
containing 1 right angle.

__Right Angle:__ 90˚

**Pythagorean Theorem:** **IN ALL RIGHT TRIANGLES... a ^{2} + b^{2}
= c^{2}**

a^{2} + b^{2} = c^{2
}3^{2} + 4^{2} = x^{2
}9 + 16 = x^{2
}25 = x^{2
}x = 5

How does this work? Here's one way...

Since side **a** was 3, it
squared is 9. **b** is 4, it squared is 16...you can see I put that
with the unit pictures... if you rearrange the units of **a** and **b**
and put them together, you get the picture for **c.**

Three numbers, such as 3, 4, and 5, are called Pythagorean triples because they can be integer sides of a right triangle.

Directions: Find the integer value for x.

Now we know **a ^{2} + b^{2} = c^{2}**,
so to find

**b ^{2} = c^{2} - a^{2
}x^{2 = }289 - 225**

x^{2} = 64

x = 8

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